# Solutions to Problems 1440 - 1450

We begin with the solution to problem 1440 from volume 49, issue 3, which was inadvertently omitted last issue.

Q1440  Let $f(x)$ be a polynomial with degre 2012, such that $f(1) = 1,\quad f(2) = \frac{1}{2},\quad f(3) = \frac{1}{3},\ldots, f(2013) = \frac{1}{2013}.$